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and break it down to (x + 2)5( 3x + 1)5 = 0 (c) Here is the original equation: (4x 2 9)3 = 0 Here, the coefficient of x 2 is 4, the coefficient of x is 0, and the constant is 9 This trinomial factors into the product of (2x + 3) and (2x 3) Therefore, we can rewrite the original equation as [(2x + 3)(2x 3)]3 = 0 and break it down to (2x + 3)3(2x 3)3 = 0 4 In each case, we can remove the exponents from the binomials, and then consider each binomial separately as a first-degree equation when it is set equal to 0 The real roots of the higher-degree equation are equal to the solutions of the first-degree equations The multiplicity of each root is the power to which its associated binomial is raised (a) The real roots are found by solving x 1=0 and x 2=0 Those roots are x = 1 or x = 2 Because each binomial is squared, each of these roots has multiplicity 2 (b) The real roots are found by solving x+2=0 and 3x + 1 = 0 Those roots are x = 2 or x = 1/3 Because each binomial is raised to the fifth power, each of these roots has multiplicity 5 (c) The real roots are found by solving 2x + 3 = 0

The previous example discussed a natural use of stochastic process theory to calculate the PSD and correlation of the output of a linear system output driven by white noise In at least two cases, the reverse process is of interest: 1 When the output autocorrelation function for a linear system with white noise inputs is known, and it is desired to nd the linear system transfer function 2 When the actual noise driving a process is colored, it may be more convenient for analysis to treat the colored noise as the output of a linear system driven by white noise Finding the appropriate linear system model is equivalent to solving Item 1 In either case, an autocorrelation function is given for a WSS stochastic process and the objective is to determine a linear system (represented by a transfer function G(s)) and a white noise process (represented by a PSD 2 w ) such that the output of the linear system driven by the white noise process yields the speci ed autocorrelation function Example 415 In the single channel error model of eqn (349), assume that the additive gyro measurement error g is determined to have the autocorrelation function R g ( ) = 10 4 e 10| | rad s

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sensor, ICs, and most other parts, but less the gain switch, can be from Fat Quarters Software for about $8000 Are you ready to begin constructing the flux-gate magnetometer Before we begin you will want to secure a well lit and well ventilated work area, as well as a bench or large table for assembling your magnetometer project Locate a small pencil-tipped 27 to 33 watt soldering iron, as well as a roll of 22 ga 60/40 tin/lead rosin core solder Go to your local Radio Shack store and purchase a small jar of Tip Tinner ; this is a soldering iron tip cleaner/dresser compound, which works wonders You will also need a few hand tools for the project You will need a pair of small end-cutters, a pair of needle-nose pliers, a pair of tweezers, and a magnifying glass A small flat-blade screwdriver and a small Phillips screwdriver should round out your tool requirements While you could build the magnetometer project on a perf-board or you could use point-point wiring it is recommended that you build the circuit on a printed circuit board for most reliable circuit operation and long life Prepare your circuit board, and then we will be able to go ahead and build the magnetometer receiver project Locate all of the project diagram, such as the schematic, parts layout diagrams and the component pin-out sheets as well as the resistor and capacitor identification tables and we will be almost ready to begin Place all of the magnetometer project components on the work bench in front of you, warm up your soldering iron and let s get going

and 2x 3 = 0 Those roots are x = 3/2 or x = 3/2 Because each binomial is cubed, each of these roots has multiplicity 3 5 Here s the original binomial factor equation, which we have been told to solve and scrutinize: (x 3/2)2(2x 7)2(7x)3( 3x + 5)5 = 0 Let s set each binomial equal to 0, and then solve the resulting first-degree equations Those equations are x 3/2 = 0 2x 7 = 0 7x = 0 3x + 5 = 0 The solutions to these first-degree equations, and therefore the real roots of the higherdegree equation, are x = 3/2 or x = 7/2 or x=0 or x = 5/3

(451)

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